delete a combination of string with sed

Question

I delete some strings in the lines of a text with sed command:

sed 's:\(pattern\.\)::g' file

But certain patterns have letters and numbers:

sed 's:\(pattern\.\|pattern1\.\|pattern2\.\|pattern23\.\|patternx\.\|patternYx\.\)::g' file

a long etc...

How to delete pattern (always is the same) + numbers (any combination 0-9) and letters (A-Z, a-z) in one single line, to avoid repeat "pattern+something"

Thanks

Answer 1

To remove pattern followed by zero or more numbers or letters followed by ., use:

sed 's:pattern[[:alnum:]]*\.::g'

Notes:

1. The regex doesn't use the parens grouping, \(...\), so I removed it.

2. [[:alnum:]] matches any letter or number.

3. [[:alnum:]]* matches zero or more of any letter or number.