I have a 2-dimensional array and I am passing it into a function to carry out certain operations. I'd like to know the correct way of doing it...
#define numRows 3 #define numCols 7 #define TotalNum (numRows*numCols) int arr[numRows][numCols] = {{0,1,2,3,4,5,6}, {7,8,9,10,11,12,13},{14,15,16,17,18,19,20}}; void display(int **p) { printf("\n"); for (int i = 0; i< numRows;i++) { for ( int j = 0;j< numCols;j++) { printf("%i\t",p[i][j]); } printf("\n"); } } int main() { display(arr); }
I get an error message:
'display': cannot convert parameter1 from 'int' to 'int*'
Is this the correct way of passing a 2-dimensional array into a function? If not, what is the correct way?
// The following program works only if your compiler is C99 compatible. If compiler is not C99 compatible, then we can use one of the following methods to pass a variable sized 2D array. In this method, we must typecast the 2D array when passing to function.
from array import * # import all package related to the array. arr1 = [[1, 2, 3, 4], [8, 9, 10, 12]] # initialize the array elements. print(arr1) # print the arr1 elements. # Use the insert() function to insert the element that contains two parameters.
You should declare your function like this:
void display(int p[][numCols])
This C FAQ thoroughly explains why. The gist of it is that arrays decay into pointers once, it doesn't happen recursively. An array of arrays decays into a pointer to an array, not into a pointer to a pointer.
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